# Basic Engineering Circuit Analysis, Problem Solving by J. David Irwin, R. Mark Nelms

By J. David Irwin, R. Mark Nelms

Irwin's uncomplicated Engineering Circuit research has equipped an outstanding popularity for its hugely obtainable presentation, transparent reasons, and broad array of worthwhile studying aids. Now in a brand new 8th variation, this hugely available ebook has been fine-tuned and revised, making it greater or even more straightforward to exploit. It covers such issues as resistive circuits, nodal and loop research thoughts, capacitance and inductance, AC steady-state research, polyphase circuits, the Laplace remodel, two-port networks, and lots more and plenty extra.

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VX′ 12 + - 3k + - 2VX′ 6k + V0 C - Fig. 5(a) We employ the prime notation on the control variable Vx since the circuit in Fig. 5(a) is different than the original network. Applying KVL to the left side of the network yields -12 +Vx′ + 2Vx′ = 0 Vx′ = 4V Then the open circuit voltage is V0 C = 2VX ′ = 8V since there is no current in the 6kΩ resistor and therefore no voltage drop across it. 40 Because of the presence of the dependent source we cannot simply look back into the open circuit terminals, with all independent sources made zero, and determine the Thevenin equivalent resistance.

6 and plot the response including the time interval just prior to closing the switch. 1 F 120 t=0 12V + - i 0 (t ) 24Ω 24Ω Fig. 1 We begin our solution by redrawing the network and labeling all the components as shown in Fig. 1(a) R 3 i X (t ) -+ t=0 12V R1 R4 R5 C R2 i 0 (t ) Fig. 1(a) In order to determine the initial condition of the network prior to switch action, we must determine the initial voltage across the capacitor. A circuit, which can be used for this purpose, is shown in Fig. 1(b).

5 Given the network in Fig. 05F Fig. 6 Find i 0 (t ) for t > 0 in the circuit in Fig. 6 and plot the response including the time interval just prior to closing the switch. 1 F 120 t=0 12V + - i 0 (t ) 24Ω 24Ω Fig. 1 We begin our solution by redrawing the network and labeling all the components as shown in Fig. 1(a) R 3 i X (t ) -+ t=0 12V R1 R4 R5 C R2 i 0 (t ) Fig. 1(a) In order to determine the initial condition of the network prior to switch action, we must determine the initial voltage across the capacitor.